Question

A solution is 0.225M Na2SO4. What is the molarity of the sodium ion in solution

Answer 1

The molarity of the sodium ion in the solution is 0.450 M.

How do we determine the molarity of sodium ions in a solution?

The molarity of the sodium ion in a solution can be determined by the dissociation of the given solution Na2SO4(sodium sulfate).

The dissociation of Na2SO4 is computed as follows:

• 1 mole of Na2SO4 dissociates to give 2 moles of sodium cations and 1 mole of sulfate anion.

i.e.

$\mathbf{Na_2SO_4 \to 2Na^{+} + SO_4^{2-}}$

The molarity for sodium-ion [Na+] is:

= 2 × 0.225 M

= 0.450 M

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