The age of the bone given that it contains C-14 and N-14 in ratio of 1:3 is 11460 years
How to determine the percentage remaining
C-14 is usually used for radioactive dating (i.e to determine the aga of substance)
From the question, C-14 and N-14 exist in ratio of 1:3.
thus, the amount of C-14 remaining can be obtained as follow:
- Ratio of C-14 = 1
- Ratio of N-14 = 3
- Total ratio = 1 + 3 = 4
- Percentage of C-14 remaining =?
Percentage of C-14 remaining = 1/4 × 100
Percentage of C-14 remaining = 25%
How to determine the number of half-lives that has elapsed
- Original amount (N₀) = 100%
- Amount remaining (N) = 25%
- Number of half-lives (n) =?
2ⁿ = N₀ / N
2ⁿ = 100 / 25
2ⁿ = 4
2ⁿ = 2²
n = 2
How to determine the age
- Half-life of C-14 (t½) = 5730 years
- Number of half-lives (n) = 2
- Time (t) = ?
t = n × t½
t = 2 × 5730
t = 11460 years
Learn more about half life:
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