Question

a waste collection tank can hold 18,754 ?

Answer 1

Density = mass / Volume 
Volume = mass / density 
= (18,754 kg) / (0.788 g/cm^3) 
= 23,800 kcm^3 
= 23,800 × 10^3 cm^3 

Answer 2

Answer:

The volume of the waste collection tank is $2.38\times 10^7 cm^3$.

Explanation:

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Density of methanol= $d = 0.788  g/cm^3$

Mass of methanol= 18,754 kg  = 18,754,000 g( 1 kg = 1000 g)

Volume of the methanol = V

Putting values in above equation, we get:

$0.788 g/cm^3=\frac{18,754,000 g}{V}$

$V=\frac{18,754,000 g}{0.788  g/cm^3}$

$V=23,799,492.38 cm^3=2.38\times 10^7 cm^3$

V = Volume of the methanol = Volume of waste collection tank

The volume of the waste collection tank is $2.38\times 10^7 cm^3$.