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A cube of metal of side 10cm is fully immersed in a liquid of relative density 0.8.Calculate the upthrust experienced by the body. Take density of water=1000kgm3 and g=10ms-1​

Respuesta :

The upthrust experienced by the cube of metal is determined as 7.84 N.

Upthrust experienced by the body

The upthrust experienced by the body is calculated as follows;

Fu = ρVg

where;

  • ρ is density of the body
  • V is volume of the body
  • g is acceleration due to gravity

Density of the body

S.G = density of the body / density of water

density of the body = S.G x density of water

ρ = 0.8 x 1000 kg/m³

ρ = 800 kg/m³

Volume of the body

V = L³

V = (0.1)³

V = 0.001 m³

Upthrust = ρVg

Upthrust = 800 x 0.001 x 9.8

Upthrust = 7.84 N

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