The phenotypic ratio of their offspring would be 1/4 each for black eyes/green skin, black eyes/white skin, orange eyes/green skin, and orange eyes/white skin respectively.
The male would be heterozygous since he has a parent that is homzygous recessive.
Assuming that eye color is A/a and skin color is B/b.
The genotype of the male would be: AaBb
The genotype of the female would be: aabb
AaBb x aabb
Progeny
A_B_ = Black eyes, green skin = 1/4
aaB_ = orange eyes, green skin = 1/4
A_abb = black eyes, white skin = 1/4
aabb = 1orange eyes, white skin = /4
See the attached image for the Punnet's square analysis.
More on dihybrid crossing can be found here: https://brainly.com/question/1185199
#SPJ9