Question

A transformer has two coils. Coil A has 75 turns and coil B has 100 turns. In the first instance, coil A is used as the primary coil, which is connected to an ac current source. As a result, the peak voltage of the secondary coil, B, has a value VP. Then, coil B is used as the primary coil and coil A becomes the secondary coil. The ac current source is then adjusted to deliver the same current to coil B as it did to coil A in the first instance. For this case, how does the peak voltage of the secondary coil, A, compare with VP.

Answer 1

The peak voltage based on the information given will be 1.33V.

How to calculate the voltage?

From the information given, Coil A has 75 turns and coil B has 100 turns.

The voltage will be:

IVa = IVb

We will then substitute the values. c

V = 100/75

V = 1.33V

Therefore, the peak voltage based on the information given will be 1.33V.

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