Question

A flywheel is rotating at 30 rev/s. What is the total angle, in radians, through which a point on the flywheel rotates in 40 s?

Answer 1

The total angle, in radians, through which a point on the flywheel rotates is 7540 radians

Angular motion

From the question, we are to determine the total angle in radians

Using the formula,

$\omega = \frac{\theta}{t}$

Where $\omega$ is the angular velocity

$\theta$ is the angle

and t is the time

From the given information,

$\omega = 30 \ rev/s$

Convert to rad/s

$\omega = 30 \times 2\pi \ rad/s$

$\omega = 188.496 \ rad/s$

and t = 40 s

From the formula

$\omega = \frac{\theta}{t}$

$\theta = \omega t$

∴ $\theta = 188.496 \times 40$

θ = 7539.822 rad

θ ≅ 7540 rad

Hence, the total angle, in radians, through which a point on the flywheel rotates is 7540 radians

Learn more on Angular motion here: https://brainly.com/question/13915983

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