Question

What is the final temperature (in °C) of 750.1 g of water (specific heat = 4.184 J/g･°C) at 24.20°C that absorbed 950.0 J of heat?

Answer 1

Answer:

... r ra to to isis bty is hdig

Answer 2

Q=mcΔt

Δt=Q/mc

t-24.2 = 950/(750.1 x 4.184)

t=24.5 °c