Question

A polynomial function has a root of -6 with multiplicity 3 and a root of 2 with multiplicity 4. If the function has a negative
leading coefficient and is of odd degree, which could be the graph of the function?

Answer 1

Answer:

Using the formula multiplicity, we find that the equation of the function will be $f(x)=-(x+6)^{3} (x-2)^{4}$. The graph is in the attachment.

Step-by-step explanation:

Concept: Given that for -6, multiplicity is 3 and for 2 multiplicity is 4.

So, the equation of multiplicity is represented as:

$f(x)=a(x-root)^{mutliplicity}$

This gives the following function

$f(x)=a(x+6)^{3} (x-2)^{4}$

The equation has a negative leading coefficient.

This means that, the value of a is less than 0 i.e. a < 0

Assume any value of a (say a = -1), the equation becomes

$f(x)=-(x+6)^{3} (x-2)^{4}$

The graph is in the attachment.

For more explanation, refer the following link:

https://brainly.com/question/13082450

#SPJ10

Answer 2

Answer:

C

Step-by-step explanation:

trust bro