The mean and the standard deviation are 233 and 208.95 respectively.
The mean of a distribution is its average, while the standard deviation is the summary of how far each data in the dataset, is to the mean.
First, we calculate the class midpoint (x) from the given intervals.
The class midpoint is the average of the intervals. So, we have:
X1 = (0+199)/2 = 99.5
X2 = (200+399)/2 = 299.5
X3 = (400+599)/2 = 499.5
X4 = (600+799)/2 = 699.5
X5 = (800+999)/2 = 899.5
X6 = (1000+1199)/2 = 1099.5
X7 = (1200+1399)/2 = 1299.5
So, the table becomes:
X values Frequency (f)
99.5 345
299.5 97
499.5 52
699.5 21
899.5 9
1099.5 8
1299.5 3
The mean of the distribution is:
This gives:
Mean = (99.5*345)+(299.5*97)+(499.5*52)+(699.5*21)+(899.5*9)+(1099.5*8)+(1299.5*3)/(345+97+52+21+9+8+3)
Mean = 124832.5/535 = 233
Therefore, Mean = 233
The standard deviation is calculated as follows:
So, we have:
Б =
√(99.5*(345-233)²+((299.5-233)² * 97)+((499.5-233)² * 52)+((699.5-233)² * 21)+((899.5-233)² * 9)+((1099.5-233)² * 8)+((1299.5- 233)² * 3)/ (345+97+52+21+9+8+3)
Standard Deviation = √(23357155.5)/535
= √43658.23
= 208.95
Б = 208.95
Hence, the mean and the standard deviation are 233 and 208.95 respectively.
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