Answer:
Given sequence in the table is a Geometric sequence and The sum for term 5 through term 11 in sigma notation is given by:
[tex]$\sum_{n=5} ^{\111} 2(-5)^n^-^1$[/tex]
Step-by-step explanation:
Geometric sequence - it is a sequence of non-zero numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio
here the given terms :
a1 = 2, a2 = -10, a3 = 50
you can see it is a geometric sequence as the ratio is constant [tex]\frac{a2}{a1}{=}\frac{a3}{a2}{=}{-5}[/tex]
now the nth term for geometric sequence :
[tex]a_{n} {=}{a}{r}^{n-1}[/tex]
here,
now substituting the given values in the expression,
[tex]a_{n} {=}{2}{{(}-5}{)}^{n-1}[/tex]
we have to find the sum from term 5 to term 11,
therefore using sigma notation and putting n= 5 and n=11 at the below and above the sigma respectively,
[tex]$\sum_{n=5} ^{\111} 2(-5)^n^-^1$[/tex]
learn more about geometric progression at brainly.com/question/4853032
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