Answer:
Slope-intercept form: y = 3x - 1
Step-by-step explanation:
We are given that a line passes through the point (-5, -16) and has a slope of 3
We want to write the equation in point-slope form, and simplify it to slope-intercept form (if it is possible to do so).
First, point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point
We have both the slope and a point, but let's label the values of everything to avoid confusion + mistakes:
m = 3
[tex]x_1=-5\\y_1=-16[/tex]
Now substitute into the formula (remember: we have NEGATIVE numbers, and the formula uses SUBTRACTION):
[tex]y--16=3(x--5)[/tex]
The equation can be simplified
[tex]y+16=3(x+5)[/tex]
We can also write this in slope-intercept form
Start by distributing 3 to both x and 5 (multiply both x and 5 by 3)
[tex]y+16=3x + 15[/tex]
Subtract 16 from both sides
y = 3x - 1