Question

which exponential function has an initial value of 2?

Answer 1

Answer:

The function $2(3^x)$ has an initial value of $2$.

Step-by-step explanation:

An exponential function is a mathematical function of the following form: $f(x)=a^x$where x is a variable, and a is a constant called the base of the function. The most commonly encountered exponential-function base is the transcendental number e, which is equal to approximately 2.71828. The exponential value can be found by solving the expression to proceed with a solution.

At the initial value,  the exponential function is in the $y$ direction and $x$ is $0$ .

$f(x)=2(3^x)\\f(x)=2(3^0)\\f(x)=2$

Therefore, the function that has an initial value of $2$ is $2(3^x)$.

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