Please help! I am stuck on this

Answer:
c.
Step-by-step explanation:
Assuming we are not restricting the domain of f, the inverse isn't a function
[tex] \frac{1}{ {x}^{2} } - 7[/tex]
[tex]y = \frac{1}{ {x}^{2} } - 7[/tex]
[tex]x = \frac{1}{ {y}^{2} } - 7[/tex]
[tex]x + 7 = \frac{1}{ {y}^{2} } [/tex]
[tex] {y}^{2} = \frac{1}{x + 7} [/tex]
[tex]y = \sqrt{ \frac{1}{x + 7} } [/tex]
Since square root are Positve or negative, the function will not be a function.
The correct answer is c.