Respuesta :

Answer:

c.

Step-by-step explanation:

Assuming we are not restricting the domain of f, the inverse isn't a function

[tex] \frac{1}{ {x}^{2} } - 7[/tex]

[tex]y = \frac{1}{ {x}^{2} } - 7[/tex]

[tex]x = \frac{1}{ {y}^{2} } - 7[/tex]

[tex]x + 7 = \frac{1}{ {y}^{2} } [/tex]

[tex] {y}^{2} = \frac{1}{x + 7} [/tex]

[tex]y = \sqrt{ \frac{1}{x + 7} } [/tex]

Since square root are Positve or negative, the function will not be a function.

The correct answer is c.

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