Question

Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distance (in meters). Find v when u is 6 m/s, a is 3 m/s², and s is 29 meters. A. 210−−−√ m/s B. 15 m/s

Answer 1

Answer:

When the initial velocity is 6m/s and acceleration is 3m/s², the final velocity after a distance of 29m is √210m/s.

Step-by-step explanation:

Concept: In the problem it is given that u = 6m/s, a = 3m/s² and s = 29m. We need to find the v. In such kinematical problems, we have an equation v² = u² + 2as. From this relation we can find v.

v² = 6² + 2×3×29

v² = 36 + 174

v² = 210

v = √210 m/s

So, the final velocity is the under-root of 210 or √210 m/s.

For more explanation, refer the following link

https://brainly.com/question/17158762

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