Question

Find the equation of the line that is perpendicular to y=-2x-9 and contains the points (8,-4)

Answer 1

The slope of the given line is -2, and since perpendicular lines have negative reciprocal slopes, the slope of the line we want to find is 1/2.

Substituting into point-slope form,

$y+4=\frac{1}{2}(x-8)\\\\y+4=\frac{1}{2}x-4\\\\\boxed{y=\frac{1}{2}x-8}$

Answer 2

Answer:

Equation of line perpendicular to y= -2x-9 is y=x/2-8 .

Step-by-step explanation:

The slope of a line gives the measure of its steepness and direction. The slope of a curve at a point is equal to the slope of the straight line that is tangent to the curve at that point.

The general equation of a line is y = mx + c, where m is the slope of the line and c is the y-intercept. It is the most common form of the equation of a straight line that is used in geometry.

The product of slopes of two perpendicular lines gives (-1).

m1m2=(-1)

(-2)m2=(-1)

m2=1/2

y=m2x+c

Point (8,-4) satisfies the given equation :

(-4)=1/2 x 8 + c

c = (-8)

Line perpendicular to y= -2x-9 will be -

y=x/2-8

Learn more about equation of lines -https://brainly.com/question/27263630

#SPJ10