Question

What is the inverse o 4x^2 x 2?

Answer 1

The inverse of $4x^{2} * 2$ are $f^{-}(x) = \frac{\sqrt{x} }{2\sqrt{2} } and - \frac{\sqrt{x} }{2\sqrt{2} }$

What id an inverse of a function?

An inverse in mathematics is a function that "undoes" another function. In other words, if f(x) produces y, then y entered into the inverse of f produces x. An invertible function is one that has an inverse, and the inverse is represented by the symbol $f^{-1}$.

Step wise procedure:

∵f(x) = $4x^{2}*2$

⇒f(x) = $8x^{2}$

replace f(x) with y

⇒y = $8x^{2}$

now, interchange the variables

⇒x = $8y^{2}$

solve for y

⇒y = $\frac{\sqrt{x} }{2\sqrt{2} }$

⇒y = - $\frac{\sqrt{x} }{2\sqrt{2} }$

solve for y and replace with $f^{-}(x)$

$f^{-}(x)$ = $\frac{\sqrt{x} }{2\sqrt{2} }$ , $-\frac{\sqrt{x} }{2\sqrt{2} }$

Learn more about Inverse function here https://brainly.com/question/15066392

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