wingr97
contestada

WILL GIVE THE BRAINLIEST!

If r and s are real numbers such that
r>s>0, then

(A) -s>-r> 0.
(B) 0>-r> -s.
(C) 0> -s> -r.
(D) -s>0> -r.
(E) -r> -s > 0.

Respuesta :

Answer:  Choice (C)  0> -s> -r

==========================================================

Explanation:

Let's consider an example. Pick any two positive numbers for r and s, where r is larger than s. I'll go with these:

  • r = 5
  • s = 2

We see that r > s is true since 5 > 2 is true

Also both are larger than 0 so we can say r > 0 and s > 0

This all combines into r > s > 0 being the case.

If we negate each number, then -r > -s would no longer be true. Use a number line to see that -5 is to the left of -2, so -5 > -2 is not true. Instead it would be -5 < -2

You can think of it like floors on a skyscraper. Positive numbers are above ground, while negative numbers are below ground in the basement levels. See the diagram below.

So -r > -s must be -r < -s instead. Both are smaller than 0

-r < 0 and -s < 0

This combines to -r < -s < 0

Flip everything and swap the outer sides to get 0 > -s > -r which leads us to choice C as the final answer

Ver imagen jimthompson5910
RELAXING NOICE
Relax