In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL) have a mean of3.1 and a standard deviation of 16.6. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table.LOADING... Click here to view page 1 of the standard normal distribution table.LOADING... Click here to view page 2 of the standard normal distribution table.LOADING... What is the confidence interval estimate of the population mean ?

The confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.

A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. The 95 percent confidence level is the most common, but other levels, like 90 percent or 99 percent, are occasionally used when computing a confidence interval.

Given in a test of effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form.Both before and after the therapy, cholesterol levels were assessed.

LDL cholesterol variations had a mean of 4.4 and a standard deviation of 19.4 (in mg/dL). The best point estimate is 4.4.

We have to find 95% confidence interval estimate of the population mean

So,

x-bar = 4.4

ME = 1.96 = 5.27

H: no difference

Ha: is a difference

We fail to reject H since 0 is in the CI.

Hence the confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.

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