Question

Two capitals invested in shares of the stock market add up to $180,000, which

have been placed at 13% and 16% annual simple interest for 3 years and 6 years

respectively. If between the two a total interest of $98,250 was obtained, determine:

What was the amount of capital invested?

Answer 1

The amount invested in the account that earns 13% simple interest is $130,789.47.

The amount invested in the account that earns 16% simple interest is $49,210.53.

What are the linear equations that represent the question?

a + b = 180,000 equation 1

0.39a + 0.96b = $98,250 equation 2

Where:

• a = amount invested in the account that earns 13% simple interest
• b  = amount invested in the account that earns 16% simple interest

How much was invested in each account?

Multiply equation 1 by 0.39

0.39a + 0.39b = 70,200 equation 3

Subtract equation 3 from equation 2

$28,050 = 0.57b

b = $49,210.53

Subtract $49,210.53 from 180,000 : 180,000 - $49,210.53 = $130,789.47

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