Please help with this difficult one...

The composite function is given as follows:
[tex](f \circ g)(x) = \frac{2x + 6}{3x + 22}[/tex]
The domain of the composite function is: [tex]\mathbb{R} - \left\{-\frac{22}{3}, 3\right\}[/tex]
The composite function is given by:
[tex](f \circ g)(x) = f(g(x))[/tex]
In this problem, the functions are:
Hence the composite function is:
[tex](f \circ g)(x) = f\left(\frac{13}{x + 3}\right) = \frac{2}{\frac{13}{x + 3} + 3} = \frac{2(x + 3)}{13 + 3(x + 3)} = \frac{2x + 6}{3x + 22}[/tex]
For the domain, we have to remove the points outside the domain of both the primitive and the composite functions, that is, the zeroes of the denominators, hence:
[tex]x + 3 \neq 0 \rightarrow x \neq 3[/tex]
[tex]3x + 22 \neq 0 \rightarrow x \neq -\frac{22}{3}[/tex]
Hence the domain is:
[tex]\mathbb{R} - \left\{-\frac{22}{3}, 3\right\}[/tex]
More can be learned about composite functions at https://brainly.com/question/13502804
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