Question

Jej pls help i need help thank you

Answer 1

Answer:

Largest total : $\mathsf {\frac{69}{20}}$

Smallest total : $\mathsf {\frac{121}{40} }$

Step-by-step explanation:

Finding the largest total :

• The greatest 2 numbers are 7/4 and 1 7/10
• ⇒ 7/4 + 1 7/10
• ⇒ 7/4 + 17/10
• ⇒ 35/20 + 34/20
• ⇒ 69/20

Finding the smallest total :

• ⇒ 1 3/8 + 33/20
• ⇒ 11/8 + 33/20
• ⇒ 55/40 + 66/40
• ⇒ 121/40

Answer 2

Answer:

Largest Totals : 69/20

Smallest Totals : 121/40

Step-by-step explanation:

Given:

Charlie adds together two of his four number cards. Find the largest and smallest totals that Charlie can make. Give your answers as improper fractions in their simplest form.  

Solve:

First let change all to improper fractions:
7/4      {already a improper fractions}

1 3/8  = 11/8

1 7/10 = 17/10

33/20       {already a improper fractions}

Thus we have:

7/4

11/8

17/10

33/20

According to the solving above ,

⇒ 70/40 , 55/40, 68/40, 66/40

⇒ 70/40 > 68/40 > 66/40 > 55/40

⇒ 7/4 > 1 7/10 > 33/20 > 1 3/8

⇒ Largest Totals : 7/4 + 1 7/10 = 69/20 = 3 9/20

⇒ Smallest Totals : 33/20 + 1 3/8 = 121/40 = 3 1/40

Since, it says given your answers as improper fractions in their simplest form:

Thus,

Largest Totals : 69/20

Smallest Totals : 121/40

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