[tex]C_{3} H_{8} +5O_{2}[/tex]→[tex]3CO_{2} +4H_{2} O[/tex]
The given reaction is of complete combustion of propane in presence of oxygen.
Molecular formula of propane gas= [tex]C_{3} H_{8}[/tex]
Combustion is a oxidation of a organic molecule into carbon dioxide and water .
Here oxygen serves as a oxidizing agent and oxidizes propane into carbo dioxide and water molecule.
The unbalanced reaction can be given as:
[tex]C_{3} H_{8} +O_{2}[/tex] →[tex]CO_{2} +H_{2} O[/tex]
Here, 3 carbons are there in propane.
so, 3 carbon dioxide molecules are formed to balance the reaction.
So, when 3 carbon dioxides are formed 3 oxygen molecules also needed.
Due to presence of 8 hydrogen in propane 4 water molecules forms , which contains 4 O means 2 oxygen molecules .
There for, total 5 molecules of oxygen are needed to balance the equation.
The final balanced equation can be given as..
[tex]C_{3} H_{8} +5O_{2}[/tex]→[tex]3CO_{2} +4H_{2} O[/tex]
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