Question

Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.

x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.

Answer 1

The correct statements are options C and option D.

• - 6x + 15 < 10 - 5x ⇒ 3rd answer

• An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

What is inequality?

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than.

The inequality is -3(2x - 5) < 5(2 - x)

At first, simplify each side

-3(2x - 5) = -3(2x) + -3(-5)

Remember (-)(-) = (+)

-3(2x - 5) = - 6x + 15

5(2 - x) = 5(2) + 5(-x)

Remember (+)(-) = (-)

5(2 - x) = 10 - 5x

- 6x + 15 < 10 - 5x

Subtract 15 from both sides

- 6x < -5 - 5x

Add 5x to both sides

- x < - 5

Remember the coefficient of x is negative, then when you divide both sides by it you must reverse the sign of inequality

The coefficient of x is -1

Divide both sides by -1

x > 5

Therefore the correct statements are options C and option D.

• - 6x + 15 < 10 - 5x ⇒ 3rd answer

• An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

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