305.6KJ are absorbed when 341 g of [tex]Ca(OH)_2[/tex]reacts via the following reaction.
What is enthalpy?
The sum of the internal energy and the product of the pressure and volume of a thermodynamic system.
Given data:
[tex]Ca(OH)_2[/tex] (s) → [tex]CaO(s)+H_2O(l)[/tex], ΔH=+65.3kJ
Moles of [tex]Ca(OH)_2[/tex]= [tex]\frac{mass}{molar \;mass}[/tex]
Moles of [tex]Ca(OH)_2[/tex] = [tex]\frac{341 g }{74g/mol}[/tex] =4.68 moles
Since, 1 mol [tex]Ca(OH)_2[/tex] absorbs 65.3kJ.
Therefore, 4.68 moles [tex]Ca(OH)_2[/tex] produce energy = 65.3kJ X 4.68 moles
=305.6KJ
Hence, 305.6KJ are absorbed when 341 g of [tex]Ca(OH)_2[/tex] reacts via the following reaction.
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