Question

How many moles of CH3CH2Br are contained in 422 mL of 0.0950 M CH3CH2Br solution?

Answer 1

M= moles/L

422mL = 422/1000 = 0.422 L

0.0950 M = ? moles / 0.422 L
0.0950 Moles/ L X 0.422 L = 0.0401 moles