Question

Evelyn and Meredith decided to kayak 1 mile up and then back in the Humboldt channel.


The rate of the water flowing in the channel was 2 miles per hour. The total time it took them to kayak up and back was 3 hours and 40 minutes. Assuming they were padding their double kayak at a fairly consistent rate, find the rate Evelyn and Meredith were paddling.

Answer 1

The rate of the water flowing in the channel was 2 miles per hour, the rate Evelyn and Meredith were paddling is mathematically given as

v+ = 2.29 1mile/hour

What is the rate Evelyn and Meredith were paddling?

Generally, the equation for the up and downstream motion is mathematically given as

vup=v-2

vdown=v+2

Therefore, Statement interpretation

2/3=40*1/60

3+2/3hr=11/3

Where, tup+tdown=11/3

tup+tdown=11/3

1/Vup+1/vdown=11/3

Considering the LCD equation

3(v-2)(V+2)

Hence

$\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}\\\\3(v+2)+3(v-2)=11(v+2)(v-2)$

11v^2-6v-44=0

$v=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Resolving using the equation we have

v+ = 2.29 1mile/hour

v- = -1.745 mile hour

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