If a and b are real numbers and a>0 and b>0 , then ab ___0
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Answer: [tex]\textsf{ab} > \textsf{0}[/tex]
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Given: [tex]\textsf{a} > \textsf{0 and b} > \textsf{0}[/tex]
Find: [tex]\textsf{ab } \_\_\_ \textsf{ 0}[/tex]
Solution: Since we know both a and b are positive this means that if they are multiplied against each other they would produce another positive. Therefore, this would cause the statement to be ab > 0.