The mass of salt dissolved in 1.0 L of 0.010 M SO₄²⁻ is 0.67 g/l
How can we Calculate the mass of the salt dissolve in 1.0 L of 0.010 M SO₄²⁻ ?
To calculate the mass of the salt dissolved, we multiply by the mass of 1 mole to molar solubilty and lets assume we are using the anhydrous salt CaSO₄ for which the Molar Mass (M) = 136.1
Mass of the salt dissolved = Molar solubility x Molar mass
Molar Mass (M) = 136.1
Molar solubility = ?
Formula to find molar solubilty ;
Molar solubility = Square root of Solubity product (Given)
S = [tex]\sqrt{2.4 x 10^{-5} }[/tex] (Value of Solubity product is given in the question)
= 4.9 × 10⁻³
Mass of the salt dissolved = Molar solubility x Molar mass
= 4.9 × 10⁻³ x 136.1
= 0.67 g/l
Learn more about Solubility here ;
https://brainly.com/question/8591226
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