Step-by-step explanation:
I'm not sure where a is supposed to be in this equation, but I'm going to assume it's supposed to be written as either 3a x 4b = 54, or 304b = 54a. If it's something else, let me know, but I'll just answer these two for now.
1. 3a x 4b
So we know that b is equal to 9. Therefore, we can rewrite
[tex]3a \times 4b = 54[/tex]
as
[tex]3a \times 4(9) = 54[/tex]
To get rid of a multiplier on one side, divide both sides by the number you want gone. I'll use 4(9), which equals 36.
[tex]3a = 54 \div 36 = 1.5[/tex]
Then we can divide by 3 to get
[tex]a = 1.5 \div 3 = 0.5[/tex]
0.5 isn't a viable answer, so I'll try the second interpretation.
2. 304b = 54a
This one is a bit easier. All we need to do is divide both sides by 54 to get
[tex]304b \div 54 = a[/tex]
304 x 9 = 2736
2736/54 = 50.66...
Again, not a viable answer. Please edit your question to include a and I'll give it another shot!
