[tex]6Ce^{4+} + I^- + 6OH^-[/tex] → [tex]6Ce^{3+} + IO_3^- + 3H_2O[/tex] is the balanced chemical equation.
A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.
Half-reaction method:
Unbalanced chemical equation:
[tex]Ce^{4+} + I^-[/tex]→ [tex]Ce^{3+} + IO^{3-}[/tex]
Oxidation half-reaction:
[tex]I^-+ 6OH^- - 6e-[/tex] → I[tex]O^{3-} + 3H_2O[/tex]
Reduction half-reaction:
[tex]Ce4^+ + e^-[/tex] → [tex]Ce^{3+}[/tex]
Balanced chemical equation:
[tex]6Ce^{4+} + I^- + 6OH^-[/tex]→ [tex]6Ce^{3+} + IO^{3-} + 3H_2O[/tex]
Oxidation number method:
Unbalanced chemical equation:
[tex]Ce^{4+} + I^-[/tex]→ [tex]Ce^{3+} + IO^{3-}[/tex]
[tex]I^{-1} -6e^-[/tex]→ [tex]I^{+5}[/tex]
[tex]Ce^{4+} + e^-[/tex] → [tex]Ce^{3+}[/tex]
Balanced chemical equation:
[tex]6Ce^{4+} + I^{-1}[/tex] → [tex]6Ce^{3+} + I^{+5}[/tex]
or
[tex]6Ce^{4+} + I^- + 6OH^-[/tex]→ [tex]6Ce^{3+} + IO_3^- + 3H_2O[/tex]
Hence, [tex]6Ce^{4+} + I^- + 6OH^-[/tex]→ [tex]6Ce^{3+} + IO_3^- + 3H_2O[/tex] is the balanced chemical equation.
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