If each dimension is doubled, the surface area changes by increasing four times (Option C)
A square pyramid is a pyramid whose base is in the shape of a square. Its volume is given as:
V = a³ (h/3);
The surface area is given as;
A = a² + 2a √((a²/4) + h))
Where:
a = base edge
h = height
Recall the surface area equation above:
A = a² + 2a √((a²/4) + h))
if we input the original dimensions, we have:
2² + 2(2) * √((2²/4) + 3²)
= 16.65
If each dimension is doubled, then we have:
4² + 2(4) * √((4²/4) + 6²)
= 66.60
This means that the dimensions increased by 66.60/16.65
= 4
Hence the correct answer is option C.
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