Question

ow much 50% disinfectant solution must be mixed with a 40% disinfectant solution to produce 25 gal of a 43% disinfectant solution?

50%
Mixture 40%
Mixture 43%
Mixture
Amount of solution
Amount of disinfectant
Part 1 of 2
gal of the 50% solution is needed.


Part 2 of 2
gal of the 40% solution is needed.

Answer 1

The amount of disinfectant solution required are; 17.5 gallons of 40% disinfectant solution and 7.5 gallons of 50% disinfectant solution

How to solve algebra word problems?

We want to find how much 50% disinfectant solution must be mixed with a 40% disinfectant solution to produce 25 gal of a 43% disinfectant solution.

Let the quantity of 50% disinfectant solution be x.

Let the quantity of 40% disinfectant solution be y.

Thus;

0.5x + 0.4y = 25 *0.43

0.5x + 0.4y = 10.75  ------(1)

Also;

x + y = 25    ------(2)

Make x the subject in eq 2 to get;

x = 25 - y

Thus;

0.5(25 - y) + 0.4y = 10.75

12.5 - 0.5y + 0.4y = 10.75

12.5 - 0.1y = 10.75

0.1y = 12.5 - 10.75

y = 1.75/0.1

y = 17.5 gallons of 40% disinfectant solution

x = 25 - 17.5

x = 7.5 gallons of 50% disinfectant solution

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