At constant pressure and temperature, 3.0 L of nitrogen trichloride decomposes to produce 4.0 L of gases; option A.
The mole ratio of the reaction is detained from the equation of the reaction.
The equation of the reaction is given below as follows:
2 moles of nitrogen trichloride decomposes to produce 4 moles of gases.
The mole ratio of a gas is equivalent to the volume ratio of the gas.
Therefore, 3.0 L of nitrogen trichloride decomposes to produce 4.0 L of gases.
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