Question

the question is in the attached file

Answer 1

Answer:

C

Step-by-step explanation:

using

x × y = $\sqrt{x^2+y^2}$ , then

2 × 4$\sqrt{2}$

= $\sqrt{2^2+(4\sqrt{2})^2 }$

= $\sqrt{4+32}$

= $\sqrt{36}$

= 6

Answer 2

$\textsf {Applying this formula :}$

$\mathsf {(x) \times (y) =\sqrt{x^{2} + y^{2}}}$

$\textsf {Now take :}$

$\mathsf {x = 2}\\\mathsf {y = 4\sqrt{2}}$

$\mathsf {Solving :}$

$\implies \mathsf {\sqrt{(2)^{2} + (4\sqrt{2})^{2}}}$

$\implies \mathsf {\sqrt{4 + 32}}$

$\implies \mathsf {6}$