Respuesta :

Answer:

[tex](t+6)(-2t+3)^{\frac{2}{3}}[/tex]

Step-by-step explanation:

[tex]\textsf{Given expression}:[/tex]

[tex]5t(-2t+3)^{\frac{2}{3}}+2(-2t+3)^{\frac{5}{3}}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c:[/tex]

[tex]\implies 5t(-2t+3)^{\frac{2}{3}}+2(-2t+3)^{\frac{3+2}{3}}[/tex]

[tex]\implies 5t(-2t+3)^{\frac{2}{3}}+2(-2t+3)^{\frac{3}{3}}(-2t+3)^{\frac{2}{3}}[/tex]

[tex]\implies 5t(-2t+3)^{\frac{2}{3}}+2(-2t+3)(-2t+3)^{\frac{2}{3}}[/tex]

[tex]\textsf{Factor out common term }(-2t+3)^{\frac{2}{3}}:[/tex]

[tex]\implies (-2t+3)^{\frac{2}{3}}(5t+2(-2t+3))[/tex]

[tex]\textsf{Simplify}:[/tex]

[tex]\implies (-2t+3)^{\frac{2}{3}}(5t-4t+6)[/tex]

[tex]\implies (-2t+3)^{\frac{2}{3}}(t+6)[/tex]

[tex]\implies (t+6)(-2t+3)^{\frac{2}{3}}[/tex]

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