Given the data from the question, reaction 2 is 2.83 times faster compared to reaction 1
Data obtained from the question
- Molarity of reaction 1 (R₁) = 0.180 mol/L
- Molarity of reaction 2 (R₂) = 0.510 mol/L
- Comparison =?
How to determine the comparison of reaction 2 to reaction 1
We can determine how many times faster is reaction 2 to reaction by doing the following:
R₂ / R₁ = 0.510 / 0.180
R₂ / R₁ = 2.83
Cross multiply
R₂ = 2.83 × R₁
From the above illustration, we can see that reaction 2 is 2.83 times faster than reaction 1
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