Respuesta :
[tex]{\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}[/tex]
★ Sanya has a piece of land which is in the shape of a rhombus.
★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.
★ Perimeter of land = 400 m.
★ One of the diagonal = 160 m.
[tex]{\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}[/tex]
★ Area each of them [son and daughter] will get.
[tex] {\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}[/tex]
Let, ABCD be the rhombus shaped field and each side of the field be [tex]x[/tex]
[ All sides of the rhombus are equal, therefore we will let the each side of the field be [tex]x[/tex] ]
Now,
• Perimeter = 400m
[tex]\longrightarrow \tt AB+BC+CD+AD=400m[/tex]
[tex]\longrightarrow \tt x + x + x + x=400[/tex]
[tex]\longrightarrow \tt 4x=400[/tex]
[tex]\longrightarrow \tt \: x = \dfrac{400}{4} [/tex]
[tex]\longrightarrow \tt x= \red{100m}[/tex]
[tex]\therefore[/tex] Each side of the field = 100m.
Now, we have to find the area each [son and daughter] will get.
So, For [tex]\triangle[/tex] ABD,
Here,
• a = 100 [AB]
• b = 100 [AD]
• c = 160 [BD]
[tex] \therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }[/tex]
[tex]\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2} [/tex]
[tex]\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}[/tex]
[tex]\longrightarrow \tt S = 180m[/tex]
Using herons formula,
[tex] \star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star[/tex]
where
• s is the simi perimeter = 180m
• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.
Putting the values,
[tex] \longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }[/tex]
[tex]\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }[/tex]
[tex]\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }[/tex]
[tex]\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}[/tex]
[tex]\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }[/tex]
[tex]\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80[/tex]
[tex] \longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }[/tex]
Thus, area of [tex]\triangle[/tex] ABD = 4800 m²
As both the triangles have same sides
So,
Area of [tex]\triangle[/tex] BCD = 4800 m²
Therefore, area each of them [son and daughter] will get = 4800 m²
[tex]{\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}[/tex]
★ Figure in attachment.
[tex] {\underline{\rule{290pt}{2pt}}} [/tex]
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Answer:
4800 m²
Step-by-step explanation:
Properties of a Rhombus
- quadrilateral (4 sided shape)
- 2 pairs of parallel sides
- All 4 sides are equal in length
- Opposite angles are equal
- Diagonals bisect each other at 90°
- Adjacent angles sum to 180°
Therefore, a rhombus can be divided into 4 congruent right triangles by drawing the diagonals. The hypotenuse of each right triangle is the side length.
Given:
- Perimeter = 400 m
⇒ side length = 400 ÷ 4 = 100 m
Therefore, the hypotenuse of each right triangle is 100 m.
As the diagonals bisect each other (divide into 2 equal parts) at right angles, a leg length of each right triangle will be half a diagonal.
Given:
- Diagonal = 160 m
⇒ 160 ÷ 2 = 80 m
Therefore, a leg length of the right triangles is 80 m.
To find the other leg length, use Pythagoras' Theorem:
⇒ a² + b² = c²
⇒ a² + 80² = 100²
⇒ a² = 3600
⇒ a = 60 m
The leg lengths are the base and height of the right triangles.
Area of a triangle = 1/2 × base × height
⇒ Area = 1/2 × 60 × 80
⇒ Area = 2400 m²
As the land is divided into 2 equal parts, each area will be twice the area of one right triangle.
Therefore, the area that Sanya's daughter and son each get for their crops is 4800 m²
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