The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000. What is the z-score of a company employee who makes an annual salary of $54,000?
–5
–3
4
5

A z-test is a statistical test used to determine whether two population means are different when the variances are known and the sample size is large.

The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000.

Now, using z- score

z= (x-[tex]\mu[/tex])/[tex]\sigma[/tex]

z= 54000- 34000/ 4000

z= 20000/4000

z=5.

Hence, z-score of a company is 5.

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The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000. What is the z-score of a company employee who makes an annual salary of $54,000? –5 –3 4 5

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The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000. What is the z-score of a company employee who makes an annual salary of $54,000?
–5
–3
4
5