Answer:
[tex]\frac{3}{7}[/tex]
Step-by-step explanation:
let x be the value of the denominator , then fraction is
[tex]\frac{x-4}{x}[/tex]
adding 1 to numerator and denominator , gives
[tex]\frac{x-4+1}{x+1}[/tex] = [tex]\frac{1}{2}[/tex]
[tex]\frac{x-3}{x+1}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2(x - 3) = x + 1
2x - 6 = x + 1 ( subtract x from both sides )
x - 6 = 1 ( add 6 to both sides )
x = 7
then original fraction
= [tex]\frac{7-4}{7}[/tex] = [tex]\frac{3}{7}[/tex]