Answer:
[tex]3x-2y < 6[/tex]
Step-by-step explanation:
First of all, we need to identify the equation of the line. x and y intercepts are known, so we can quickly write the line as
[tex]\frac x 2 + \frac y{(-3)} = 1 \rightarrow 3x-2y=6[/tex] That gives us the last two options. To solve it let's plug a convenient point - read: the origin - into the equation and see which one holds true. And since for obvious reason [tex]3\cdot 0 -2 \cdot 0 =0 < 6[/tex] the valid solution is the last one.
