The friction force exerted on the 2400kg car is 9408 Newtons
What force will be exerted on the 2400kg car?
First, we know that the friction force and mass are represented by a proportional relation, this means that we can write:
F = k*M
Where F is the force, M is the mass and k is the constant of proportionality.
We know that for a 1600kg car, a force of 6272N is exerted, replacing that we get:
6272N = k*1600kg
Solving for k we get:
k = (6272N)/(1600 kg) = 3.92 N/kg
Then the proportional relationship is:
F = (3.92 N/kg)*M
So if M = 2400kg, we have:
F = (3.92 N/kg)*2400kg = 9408 N
So the friction force exerted on the 2400kg car is 9408 Newtons
If you want to learn more about proportional realtions:
https://brainly.com/question/12242745
#SPJ1
