The total energy is transferred to the liquid is = 217809.9 J
It is given in the question that—
weight of the liquid= 0.3kg
specific heat capacity=22001/kg C
temperature changes between 20°C to 53°C
we can easily solve this problem by using the formula of the calorimetry principle.
The formula is —
Q= m×s×t [Q=total energy is transferred, m= mass of the substance, s= specific heat, t= final temperature - initial temperature]
by putting the value on what is given in this question —
Q= 0.3×22001×(53-20)
= 217809.9 J
So energy transferred to the liquid is=217809.9 J