Question

What is the percent yield for the reaction below when
705.0 g SO2 and 80.0 g 0₂ produce 586.0 g SO3?
2SO2(g) + O₂(g) → 2SO3(g)

Answer 1

Answer:

99•74%

Explanation:

the measured amount of product obtained in any chemical reaction is known as the actual yield so the actual yield of this question is ( 586 gram of SO3 )

Determine the theoretical yield using mass - mass relationship

705g / 192g = × / 160g = 192g × / 192g = 192g cancel by 192g the × value is equal to

705g × 160g / 192g g cancel by g the result is

112,800 g / 192 = 587• 5g//////

percentage yield = actual yield x 100 / theoretical yield

percentage yield = 586 x 100 / 587• 5 =

58,600 / 587• 5 = 99• 74 %