An equation that models the height of the ball as a function of time t is; h(t) = -16t² + 40t + 3. The maximum height that the ball will reach is 28 ft
How to Solve the Vertical velocity model?
We are given the equation for the vertical velocity model as;
h = -16t² + vt + s
Where;
v = velocity
s = starting height
h = ending height
t = time
A) From the question, we have;
v = 40 ft/s
s = 3 ft
Thus, the equation is;
h = -16t² + 40t + 3
B) To find the time that the ball reaches its maximum height, we will equate the height equation to zero and find the roots. Thus;
-16t² + 40t + 3 = 0
Using an online quadratic equation calculator gives;
t = 2.573 s
C) The maximum height that the ball will reach is;
h'(t) = -32t + 40
At h'(t) = 0;
-32t + 40 = 0
32t = 40
Thus;
t = 1.25 s
Max height = -16(1.25)² + 40(1.25) + 3
Max height = 28 ft
D) The height of the ball after 2 seconds is;
h(2) = -16(2)² + 40(2) + 3
h(2) = 19 ft
E) Time for the ball to hit the ground is;
T = 2 * 2.573
T = 5.146 s
Read more about Vertical Velocity Model at; https://brainly.com/question/27526920
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