Question

with strong heating calcium carbonate undergoes thermal decomposition how many mole of CaCO3 are there in 50g of calcium carbonate

Answer 1

Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole

Answer 2

Answer:

a)CaCO 3→CaO+CO 2CaCO3→CaO+CO2

b) Moles of CaCO3=4.37moles

c) I) Mass of calcium oxide =28g

ii)Mass of carbon dioxide=16.7g

iii)Volume=203cm3