If a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
The mass percent of hydrate in a sample can be calculated by dividing the mass of water in the sample by the mass of the hydrated compound.
According to this question, 3.50g sample of an hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate. The mass percent of water is calculated as follows:
Mass percent of water = (3.5-2.1)/3.5 × 100
Mass percent of water = 40%
Therefore, if a 3.50g sample of the hydrate of copper (II) sulfate is heated to yield 2.10g of anhydrous copper (II) sulfate, the mass percent of water in the hydrate is 40%.
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