What is the perimeter of this triangle?

Answer: [tex]a+b+\sqrt{a^{2}+b^{2}}[/tex]
Step-by-step explanation:
The distance from (0,b) to (0,0) is b.
The distance from (0,a) to (0,0) is a.
Using the Pythagorean theorem, the distance from (0,b) to (a,0) is [tex]\sqrt{a^{2}+b^{2}}[/tex]
So, the perimeter is [tex]\boxed{a+b+\sqrt{a^{2}+b^{2}}}[/tex]