Question

If ƒ(x ) = x 2 + 1 and g(x ) = 3x + 1, find ƒ(-1) + 5g(-3).

-40
-38
7

Answer 1

$f(x) = x^2 + 1 \\ g(x) = 3x + 1$

You can do this in parts.
$f(-1) = (-1)^2 + 1 = 1 + 1 = 2$
g(-3) = 3(-3) + 1 = -9 + 1 = -8
So, 5g(-3) = 5(-8) = -40.
So f(-1) + 5g(-3) = 2 - 40 = -38

Or you can do this as one big chunk.
f(-1) + 5g(-3)
$=[(-1)^2+1] + 5[3(-3) + 1] \\ = (2) + 5(-9 + 1) \\ = 2 + 5(-8) \\ = 2 - 40 \\ = -38$

Answer 2

easy

f(-1)=(-1)²+1
f(-1)=1+1
f(-1)=2

5g(-3)=5(3(-3)+1)
5g(-3)=5(-9+1)
5g(-3)=5(-8)
5g(-3)=-40


f(-1)+5g(-3)=2-40=-38


answer is -38