Question

what are the vertex and axis of symmetry of the equation y=2x^2+16x-12

Answer 1

$y=2x^2+16x-12\\y=2(x^2+8x-6)\\ y=2(x^2+8x+16-22)\\ y=2(x+4)^2-44\\\\ \text{The axis of symetry is }y=-4$